Optimal. Leaf size=545 \[ -\frac{2 \sqrt{2} \sqrt{b^2-4 a c} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (a e^2-b d e+c d^2\right ) \sqrt{\frac{c (d+e x)}{2 c d-e \left (\sqrt{b^2-4 a c}+b\right )}} (5 A c e-4 b B e+3 B c d) \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt{\frac{\sqrt{b^2-4 a c}+b+2 c x}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right ),-\frac{2 e \sqrt{b^2-4 a c}}{2 c d-e \left (\sqrt{b^2-4 a c}+b\right )}\right )}{15 c^3 e \sqrt{d+e x} \sqrt{a+b x+c x^2}}+\frac{\sqrt{2} \sqrt{b^2-4 a c} \sqrt{d+e x} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (B \left (-c e (9 a e+13 b d)+8 b^2 e^2+3 c^2 d^2\right )+10 A c e (2 c d-b e)\right ) E\left (\sin ^{-1}\left (\frac{\sqrt{\frac{b+2 c x+\sqrt{b^2-4 a c}}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right )|-\frac{2 \sqrt{b^2-4 a c} e}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{15 c^3 e \sqrt{a+b x+c x^2} \sqrt{\frac{c (d+e x)}{2 c d-e \left (\sqrt{b^2-4 a c}+b\right )}}}+\frac{2 \sqrt{d+e x} \sqrt{a+b x+c x^2} (5 A c e-4 b B e+3 B c d)}{15 c^2}+\frac{2 B (d+e x)^{3/2} \sqrt{a+b x+c x^2}}{5 c} \]
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Rubi [A] time = 0.784095, antiderivative size = 545, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.172, Rules used = {832, 843, 718, 424, 419} \[ -\frac{2 \sqrt{2} \sqrt{b^2-4 a c} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (a e^2-b d e+c d^2\right ) \sqrt{\frac{c (d+e x)}{2 c d-e \left (\sqrt{b^2-4 a c}+b\right )}} (5 A c e-4 b B e+3 B c d) F\left (\sin ^{-1}\left (\frac{\sqrt{\frac{b+2 c x+\sqrt{b^2-4 a c}}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right )|-\frac{2 \sqrt{b^2-4 a c} e}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{15 c^3 e \sqrt{d+e x} \sqrt{a+b x+c x^2}}+\frac{\sqrt{2} \sqrt{b^2-4 a c} \sqrt{d+e x} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} \left (B \left (-c e (9 a e+13 b d)+8 b^2 e^2+3 c^2 d^2\right )+10 A c e (2 c d-b e)\right ) E\left (\sin ^{-1}\left (\frac{\sqrt{\frac{b+2 c x+\sqrt{b^2-4 a c}}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right )|-\frac{2 \sqrt{b^2-4 a c} e}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{15 c^3 e \sqrt{a+b x+c x^2} \sqrt{\frac{c (d+e x)}{2 c d-e \left (\sqrt{b^2-4 a c}+b\right )}}}+\frac{2 \sqrt{d+e x} \sqrt{a+b x+c x^2} (5 A c e-4 b B e+3 B c d)}{15 c^2}+\frac{2 B (d+e x)^{3/2} \sqrt{a+b x+c x^2}}{5 c} \]
Antiderivative was successfully verified.
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Rule 832
Rule 843
Rule 718
Rule 424
Rule 419
Rubi steps
\begin{align*} \int \frac{(A+B x) (d+e x)^{3/2}}{\sqrt{a+b x+c x^2}} \, dx &=\frac{2 B (d+e x)^{3/2} \sqrt{a+b x+c x^2}}{5 c}+\frac{2 \int \frac{\sqrt{d+e x} \left (\frac{1}{2} (-b B d+5 A c d-3 a B e)+\frac{1}{2} (3 B c d-4 b B e+5 A c e) x\right )}{\sqrt{a+b x+c x^2}} \, dx}{5 c}\\ &=\frac{2 (3 B c d-4 b B e+5 A c e) \sqrt{d+e x} \sqrt{a+b x+c x^2}}{15 c^2}+\frac{2 B (d+e x)^{3/2} \sqrt{a+b x+c x^2}}{5 c}+\frac{4 \int \frac{\frac{1}{4} \left (4 b^2 B d e+c \left (15 A c d^2-12 a B d e-5 a A e^2\right )-b \left (6 B c d^2+5 A c d e-4 a B e^2\right )\right )+\frac{1}{4} \left (10 A c e (2 c d-b e)+B \left (3 c^2 d^2+8 b^2 e^2-c e (13 b d+9 a e)\right )\right ) x}{\sqrt{d+e x} \sqrt{a+b x+c x^2}} \, dx}{15 c^2}\\ &=\frac{2 (3 B c d-4 b B e+5 A c e) \sqrt{d+e x} \sqrt{a+b x+c x^2}}{15 c^2}+\frac{2 B (d+e x)^{3/2} \sqrt{a+b x+c x^2}}{5 c}-\frac{\left ((3 B c d-4 b B e+5 A c e) \left (c d^2-b d e+a e^2\right )\right ) \int \frac{1}{\sqrt{d+e x} \sqrt{a+b x+c x^2}} \, dx}{15 c^2 e}+\frac{\left (10 A c e (2 c d-b e)+B \left (3 c^2 d^2+8 b^2 e^2-c e (13 b d+9 a e)\right )\right ) \int \frac{\sqrt{d+e x}}{\sqrt{a+b x+c x^2}} \, dx}{15 c^2 e}\\ &=\frac{2 (3 B c d-4 b B e+5 A c e) \sqrt{d+e x} \sqrt{a+b x+c x^2}}{15 c^2}+\frac{2 B (d+e x)^{3/2} \sqrt{a+b x+c x^2}}{5 c}+\frac{\left (\sqrt{2} \sqrt{b^2-4 a c} \left (10 A c e (2 c d-b e)+B \left (3 c^2 d^2+8 b^2 e^2-c e (13 b d+9 a e)\right )\right ) \sqrt{d+e x} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \operatorname{Subst}\left (\int \frac{\sqrt{1+\frac{2 \sqrt{b^2-4 a c} e x^2}{2 c d-b e-\sqrt{b^2-4 a c} e}}}{\sqrt{1-x^2}} \, dx,x,\frac{\sqrt{\frac{b+\sqrt{b^2-4 a c}+2 c x}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right )}{15 c^3 e \sqrt{\frac{c (d+e x)}{2 c d-b e-\sqrt{b^2-4 a c} e}} \sqrt{a+b x+c x^2}}-\frac{\left (2 \sqrt{2} \sqrt{b^2-4 a c} (3 B c d-4 b B e+5 A c e) \left (c d^2-b d e+a e^2\right ) \sqrt{\frac{c (d+e x)}{2 c d-b e-\sqrt{b^2-4 a c} e}} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1-x^2} \sqrt{1+\frac{2 \sqrt{b^2-4 a c} e x^2}{2 c d-b e-\sqrt{b^2-4 a c} e}}} \, dx,x,\frac{\sqrt{\frac{b+\sqrt{b^2-4 a c}+2 c x}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right )}{15 c^3 e \sqrt{d+e x} \sqrt{a+b x+c x^2}}\\ &=\frac{2 (3 B c d-4 b B e+5 A c e) \sqrt{d+e x} \sqrt{a+b x+c x^2}}{15 c^2}+\frac{2 B (d+e x)^{3/2} \sqrt{a+b x+c x^2}}{5 c}+\frac{\sqrt{2} \sqrt{b^2-4 a c} \left (10 A c e (2 c d-b e)+B \left (3 c^2 d^2+8 b^2 e^2-c e (13 b d+9 a e)\right )\right ) \sqrt{d+e x} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} E\left (\sin ^{-1}\left (\frac{\sqrt{\frac{b+\sqrt{b^2-4 a c}+2 c x}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right )|-\frac{2 \sqrt{b^2-4 a c} e}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{15 c^3 e \sqrt{\frac{c (d+e x)}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}} \sqrt{a+b x+c x^2}}-\frac{2 \sqrt{2} \sqrt{b^2-4 a c} (3 B c d-4 b B e+5 A c e) \left (c d^2-b d e+a e^2\right ) \sqrt{\frac{c (d+e x)}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}} \sqrt{-\frac{c \left (a+b x+c x^2\right )}{b^2-4 a c}} F\left (\sin ^{-1}\left (\frac{\sqrt{\frac{b+\sqrt{b^2-4 a c}+2 c x}{\sqrt{b^2-4 a c}}}}{\sqrt{2}}\right )|-\frac{2 \sqrt{b^2-4 a c} e}{2 c d-\left (b+\sqrt{b^2-4 a c}\right ) e}\right )}{15 c^3 e \sqrt{d+e x} \sqrt{a+b x+c x^2}}\\ \end{align*}
Mathematica [C] time = 10.874, size = 978, normalized size = 1.79 \[ \frac{2 \sqrt{c x^2+b x+a} \left (\left (10 A c e (2 c d-b e)+B \left (3 c^2 d^2+8 b^2 e^2-c e (13 b d+9 a e)\right )\right ) \left (c \left (\frac{d}{d+e x}-1\right )^2+\frac{e \left (-\frac{d b}{d+e x}+b+\frac{a e}{d+e x}\right )}{d+e x}\right )-\frac{i \sqrt{1-\frac{2 \left (c d^2+e (a e-b d)\right )}{\left (2 c d-b e+\sqrt{\left (b^2-4 a c\right ) e^2}\right ) (d+e x)}} \sqrt{\frac{2 \left (c d^2+e (a e-b d)\right )}{\left (-2 c d+b e+\sqrt{\left (b^2-4 a c\right ) e^2}\right ) (d+e x)}+1} \left (\left (2 c d-b e+\sqrt{\left (b^2-4 a c\right ) e^2}\right ) \left (10 A c e (2 c d-b e)+B \left (3 c^2 d^2+8 b^2 e^2-c e (13 b d+9 a e)\right )\right ) E\left (i \sinh ^{-1}\left (\frac{\sqrt{2} \sqrt{\frac{c d^2-b e d+a e^2}{-2 c d+b e+\sqrt{\left (b^2-4 a c\right ) e^2}}}}{\sqrt{d+e x}}\right )|-\frac{-2 c d+b e+\sqrt{\left (b^2-4 a c\right ) e^2}}{2 c d-b e+\sqrt{\left (b^2-4 a c\right ) e^2}}\right )+\left (8 b^3 B e^3-b^2 \left (21 c d B+8 \sqrt{\left (b^2-4 a c\right ) e^2} B+10 A c e\right ) e^2+b c \left (10 A e \left (3 c d+\sqrt{\left (b^2-4 a c\right ) e^2}\right )+B \left (15 c d^2+13 \sqrt{\left (b^2-4 a c\right ) e^2} d-17 a e^2\right )\right ) e+c \left (-3 B c \sqrt{\left (b^2-4 a c\right ) e^2} d^2+3 a B e^2 \left (8 c d+3 \sqrt{\left (b^2-4 a c\right ) e^2}\right )-10 A c e \left (3 c d^2+2 \sqrt{\left (b^2-4 a c\right ) e^2} d-a e^2\right )\right )\right ) \text{EllipticF}\left (i \sinh ^{-1}\left (\frac{\sqrt{2} \sqrt{\frac{c d^2-b e d+a e^2}{-2 c d+b e+\sqrt{\left (b^2-4 a c\right ) e^2}}}}{\sqrt{d+e x}}\right ),-\frac{-2 c d+b e+\sqrt{\left (b^2-4 a c\right ) e^2}}{2 c d-b e+\sqrt{\left (b^2-4 a c\right ) e^2}}\right )\right )}{2 \sqrt{2} \sqrt{\frac{c d^2+e (a e-b d)}{-2 c d+b e+\sqrt{\left (b^2-4 a c\right ) e^2}}} \sqrt{d+e x}}\right ) (d+e x)^{3/2}}{15 c^3 e^2 \sqrt{a+x (b+c x)} \sqrt{\frac{(d+e x)^2 \left (c \left (\frac{d}{d+e x}-1\right )^2+\frac{e \left (-\frac{d b}{d+e x}+b+\frac{a e}{d+e x}\right )}{d+e x}\right )}{e^2}}}+\frac{\left (\frac{2 (6 B c d-4 b B e+5 A c e)}{15 c^2}+\frac{2 B e x}{5 c}\right ) \left (c x^2+b x+a\right ) \sqrt{d+e x}}{\sqrt{a+x (b+c x)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.054, size = 7523, normalized size = 13.8 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (e x + d\right )}^{\frac{3}{2}}}{\sqrt{c x^{2} + b x + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B e x^{2} + A d +{\left (B d + A e\right )} x\right )} \sqrt{e x + d}}{\sqrt{c x^{2} + b x + a}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (A + B x\right ) \left (d + e x\right )^{\frac{3}{2}}}{\sqrt{a + b x + c x^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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